Re: [xsl] Serious problems finding syntax

[owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx (by way of B. Tommie Usdin)]

From: "Frank Neugebauer" <neuggs@xxxxxxxxxxx>
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Serious problems finding syntax
Date: Tue, 23 Jan 2001 20:43:36
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Gavin,

Not sure if I'm reading this correctly, but it looks like your 'if'
expression is evaluating an attribute that does not exist in the source XML
(PREVIOUS_QUERY). Perhaps that should read "PREVIOUS_PAGE"?

Regards,
Frank Neugebauer.


> My node goes as follows (removing the standard header info within the XML):
> <FOOTER>
> 	<CONTENT PREVIOUS_PAGE="" NEXT_PAGE="2"></CONTENT>
> 	<CONTENT PREVIOUS_PAGE="1" NEXT_PAGE="3"></CONTENT>
> 	<CONTENT PREVIOUS_PAGE="2" NEXT_PAGE="4"></CONTENT>
> </FOOTER>
>
>
> In my XSL I have :
> <xsl:for-each select="CONTENT">
> 	<xsl:if test="@PREVIOUS_QUERY!=''">
> 		<a><xsl:attribute name="href">default.asp<xsl:value-of
> select="@PREVIOUS_QUERY" /></xsl:attribute>Previous Page</a><br/>
> 	</xsl:if>
> </xsl:for-each>
>
> This IF Statement causes NO DATA to appear.   Take out the If statement and
> all data appears as it should.
>
> --
> Gavin Landon
> Karland International
> http://www.karland.com/
>
>
>
>   XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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