Subject: Re: [xsl] Q: Passing constructed elements as parameters From: george.fink@xxxxxxx Date: Wed, 31 Jan 2001 11:44:48 -0800 |
> > > Hi, I'm trying to do something like: > > <xsl:apply-template> > <xsl:with-param name="foo"> > <xsl:element name="bar"> ... </xsl:element> > </xsl:with-param> > </xsl:apply-template> > > <xsl:template> > assuming you mean <xsl:template match="xxx"> here > > <xsl:param name="foo"/> > <xsl:for-each select="$foo/bar"/> > </xsl:template> > > But something seems to be lost in the translation. Is there some conversion > step I'm missing? > > --George > > > if the xxx element that matches the second template is a direct > child of the template that has the apply-templates code at the top > then it will see the seting of the foo parameter. (otherwise it won't as > parameters are not passed on by default) > > However if you go > > <xsl:with-param name="foo"> > .... > </xsl:with-param> > > rather than > > <xsl:with-param name="foo" select="..."/> > > > then $foo wilkl be a result tree fragment rather than a node set, > so you can not query into it with <xsl:for-each select="$foo/bar"/> > > It's not clear from what you've posted whether you want to use th e > <xsl:with-param name="foo" select="..."/> for and have $ foo > being a set of nodes in the input document, or whether you did intent to > construct a new node set, in which case you processor may have a > node-set() extension function, used as > > <xsl:for-each select="xt:node-set($foo)/bar"/> > The intent was to have it be a node set so I can query it with $foo/bar, or do a apply-templates on it if I need to. So the node-set function isn't a standard, I'm using xalan right now, if its not there I guess I need to change engines. Thanks for your help. --George XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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