Subject: [xsl] how to pass param in xsl:includes with XSLT2.0 From: Kumar Vallabhu <kvallabhu@xxxxxxxxxxxx> Date: Fri, 23 Feb 2001 14:50:50 -0800 |
Hi all, this code which worked with xslt1.1 <xsl:template name="commonheader"> <xsl:param name="page"/> <xsl:param name="pagetype"/> some thing .... </xsl:template> <xsl:include href="http://localhost:3030/com/vizional/portal/xsl/headder.xsl"/> <xsl:call-template name="commonheader"> <xsl:with-param name="pagetype" select="'Events'"/> <xsl:with-param name="owner" select="EventType/loginUser"/> <xsl:with-param name="page" select="'Config'"/> </xsl:call-template> this code does not work with XSLT2.0, it is not giving any exception but it just don't recognise param values can any help me to figure this out XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Q on how create pick list, Jeni Tennison | Thread | RE: [xsl] how to pass param in xsl:, Michael Fitzgerald |
Re: [xsl] cannot reach the inner ta, Franz Figl | Date | [xsl] Explorer Treeview with XSL, Chirag_Nangia |
Month |