Re: [xsl] Seeking XPATH

Subject: Re: [xsl] Seeking XPATH
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 6 Mar 2001 18:46:55 GMT
try again.

   B[@NM = "case1"]/text() = A[B[@NM = "case3"]/text()]

So that selects A nodes for which the filter is true.

 B[@NM = "case1"]/text()

is the node set of three text nodes

{ "&#10;     " , "&#10;     " , "&#10;      ---&#10;   " }

but in the right hand side you have the path A which looks for A
children of the current A node. I'm not sure quite what you intended,
either . or ../A presumably.


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