Subject: [xsl] about xsl:when From: dago@xxxxxxxxxxxxxxxxx Date: Thu, 8 Mar 2001 11:19:04 -0500 |
Hi all, I try that display the names that have the 'id=1' and 'id=2' in the resutl, but doesen't work. In the XML file, each 'persona' node have a 'id' with numeric value. This is the xsl code: <xsl:template match = "persona[@id]" > <xsl:choose > <xsl:when test = ".='1'" > <br/> edad=<xsl:value-of select="name"/> </xsl:when> <xsl:when test = ".='2'" > <br/> edad=<xsl:value-of select="name"/> </xsl:when> <xsl:otherwise > <br/> <xsl:text >no hay</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:template> Thnanks for you help, Dago Flores. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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