Subject: Re: [xsl] Copy XHTML element contents without base tag|
From: cutlass <cutlass@xxxxxxxxxxx>
Date: Fri, 09 Mar 2001 13:09:38 +0000
look at faq on copying http://www.dpawson.co.uk/xsl/N1930.html Nick Vincent wrote:
This is probably painfully easy, but I can't think of a solution:
I need to include a raw XHTML fragment in my XSL:
<document> <xfragment> This is a fragment of XHTML <table><tr><td> [snip dull HTML] </td></tr></table> </xfragment> </document>
Now, as far as I can see there are two ways of processing this in XSLT:
<xsl:template match="xfragment"> <xsl:copy-of select="." /> </xsl:template>
Unfortunately this ends up including the <xfragment> tags in the output, which I can't really have.
The other way I can see is
<xsl:template match="xfragment"> <xsl:copy-of select="./*" /> </xsl:template>
Unfortunately this removes any text elements which are direct children of the xfragment tags (e.g. the phrase 'This is a fragment of XHTML' in the above example).
Does anyone know any better ways of making this copy?
Nick Vincent NeoWorks
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