[xsl] RE: Copy attributes? ... possible problem in FAQ

[Nick Vincent <Nick@xxxxxxxxxxxx>]

My bad.  I've worked it out now.

Looks like there might still be a problem in the FAQ though.  I think it
should be of the form:

<xsl:template match="mytag">
	<mynewtagname>
		<xsl:for-each select="*@">
			<xsl:attribute name="{name()}"><xsl:value-of
select="." /></xsl:attribute>
		</xsl:for-each>
 		<!-- Deal with content -->
	</mynewtagname>
</xsl:template>

with additional curly braces in the <xsl:attribute> element.

Thanks,

Nick Vincent
NeoWorks

> -----Original Message-----
> From: Nick Vincent 
> Sent: 09 March 2001 15:26
> To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
> Subject: Copy attributes? ... possible problem in FAQ
> 
> 
> Hi all,
> 
> I'm trying to change a tag name and copy all of it's 
> attributes.  The suggested way of doing this in the copy FAQ 
> at www.dpawson.co.uk is this:
> 
> <xsl:template match="mytag">
> 	<mynewtagname>
> 		<xsl:for-each select="*@">
> 			<xsl:attribute 
> name="name()"><xsl:value-of select="." /></xsl:attribute>
> 		</xsl:for-each>
> 		<!-- Deal with content -->
> 	</mynewtagname>
> </xsl:template>
> 
> However, in <xsl:attribute name="" /> the name parameter is 
> of type 'qname', which is not calculated at runtime, hence 
> the actual output is:
> 
> <mynewtagname name()="value">
> 	...
> </mynewtagname>
> 
> Is there any other way of doing this?
> 
> Thanks,
> 
> 
> Nick Vincent
> NeoWorks
> 

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