Subject: Re: [xsl] How to specify a path to a node in a nodeset using a variable From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 12 Mar 2001 09:14:56 GMT |
> In my scenario, $container is a nodeset, not a nodeset expression. yes but '$container' is a string. You can use concat to join that to a string representation of the rest of the XPath expression you want to evaluate, then use saxon: or xalan: evaluate to evaluate the resulting string as an XPath expression. > Why can't we have a construct specifically for changing the current nodeset, > in my previous email I gave two alternatives. Well it depends whetehr you are discussing programming in XSLT or in a future version. Both are reasonable subjects for this list, but you get different answers depending on the context. > Does this mailing list apply only to saxon? Should I be posting > somewhere else for Xalan. No it's for XSLT in general. processor specific questions are best asked elsewhere (both saxon and xalan have their pwn developers lists, I believe) David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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