Subject: RE: [xsl] Using position() with sorted node From: "Diamond, Jason" <Jason.Diamond@xxxxxxx> Date: Tue, 13 Mar 2001 14:07:46 -0600 |
Hi, Jenny. position() does return the position of the current node in the current node list (which is created using an <xsl:apply-templates> or <x Can you show a little more of the code in question? When you say that it needs to reference the previous node, do you mean that it needs to include the string value of the previous node in the href attribute? -----Original Message----- From: Jenny Simpson [mailto:simpson@xxxxxxxxxxx] Sent: Tuesday, March 13, 2001 10:48 AM To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Using position() with sorted node I have an xml document whose nodes are being sorted according to date. I am trying to use the position() function to reference these nodes, but since they are sorted, their processing/output order is different from the original document order. Furthermore, I am using several for-each statements which make it even more difficult to use position() since the position index starts back at 1 for each different set of nodes being processed. Is there a way to use position() or a similar function to reference the position of sorted nodes? Here is an example of the code I'm looking at. This particular piece of code was written by Jeremy Quinn. Instead of day= referencing the position of the node in the output, I need it to reference the node which is processed immediately before this piece of code is executed. <a> <xsl:attribute name="href">form/item-edit.xml?day=<xsl:value-of select="position()"/></xsl:attribute> <xsl:text>[edit]</xsl:text> </a> Thanks. Jenny Simpson XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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