Subject: Re: [xsl] xsl filtering duplicate nodes From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Thu, 29 Mar 2001 14:16:30 +0100 |
Hi Tom, > I need to filter out only those nodes which have identical @id and > @found attributes One method would be to process all the Reference elements, but within the template or xsl:for-each test whether there was a preceding sibling with the same @id and @found as the current one, and only process the element if there isn't: <xsl:if test="not(preceding-sibling::Reference [@id = current()/@id and @found = current()/@found])"> ... </xsl:if> The other way is to use the Muenchian method and create a key that indexes the Reference elements based on their @id *and* @found, by concatenating the two values together: <xsl:key name="Reference-by-id-and-found" match="Reference" use="concat(@id, ':', @found)" /> You can then use: Reference[count(.|key('Reference-by-id-and-found', concat(@id, ':', @found))[1]) = 1] to get the unique Reference elements. My reply to your earlier email explained how this worked, so I won't repeat it. I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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