Subject: [xsl] Un-escape and re-transform From: Bas Alberts <bas.alberts@xxxxxxxxxxxx> Date: Tue, 10 Apr 2001 15:54:46 +0200 |
Hi All My Content Provider delivers XML files with partially escaped HTML tags, for example: <content> <web> <P>This is text.</P> <P>This is more text.</P> </web> </content> My quest is to replace the "<" by the un-escaped "<" character, and then redo the XSLT for that <P>...</P> bit. I already prepared the template(s) for <xsl:for-each select="P">. My guess is, that I can use JavaScript's unescape() function to produce the "<" and use "<xsl:apply-templates>" to redo the XSLT. But, I have no idea how to put it all together. Also, I have the suspicion that there shouldn't be any scripting required at all...? Can you help me? Regards, Bas Alberts XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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