Subject: RE: [xsl] Having trouble, please help... From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Tue, 10 Apr 2001 14:22:59 +0100 |
> I've got the following XSL template. I want to pass it four > parameters. One > for the ParentNode it should select, one for the CurrentNode > to select, and > two other text based values. > > I use the following code to implement the template: > > <xsl:call-template name="PrintRows"> > <xsl:with-param > name="ParentNode">RetrieveNameAndAddressRSResponse</xsl:with-param> > <xsl:with-param > name="CurrentNode">NameAddress1</xsl:with-param> > <xsl:with-param name="RowColor">#FFEBBF</xsl:with-param> > <xsl:with-param name="DisplayText">Holder > Name:</xsl:with-param> > </xsl:call-template> Let's be clear: you are not passing the node as a parameter, you are passing its name, represented as a string. > > and the template looks like this: > > <xsl:apply-templates > select="RetrieveNameAndAddressRSResponse/NameAddress1"> > </xsl:apply-templates> > </font></td> > <td bgcolor="#000066" width="5%"><br/></td> > <td bgcolor="#FF9933" width="5%"><br/></td> > </tr> > </xsl:template> > > Now in the above example, everything is fine, but I need to > replace the > apply-templates line with something using the two parameters passed. > Whenever I do > > <xsl:apply-templates select="$ParentNode"> > > I get a "Reference to variable or parameter 'ParentNode' must > evaluate to a node list" > Yes: because the value of the variable is a string, not a node[-set]. So long as you use simple names, you can use the construct select=*[name()=$ParentNode]". If you want to construct more complex expressions than simple names, you need the xx:evaluate() extension function available in several products. Mike Kay Software AG XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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