Subject: [xsl] Node comparison From: Kevin_Gutch@xxxxxxxxxxx Date: Sat, 14 Apr 2001 19:12:16 -0400 |
Having two different XML's joined on an entity reference I need to compare values underneath two different parent nodes without having to use a $Position Variable. The reason being is that I may not have a one to one relationship. So with an example below I would like to use my XSLT to base the values of Parent 2 on the like values in Parent 1. <?xml version="1.0" encoding="UTF-8"?> <Parent 1> <Value 1>1</Value 1> <Value 2>0</Value 2> <Value 3>1</Value 3> <Value 4>0</Value 4> </Parent 1> <Parent 2> <Value 1> </Value 1> <Value 2> </Value 2> <Value 2> </Value 2> <Value 3> </Value 3> <Value 4> </Value 4> </Parent 2> I would like the following results: <Parent 1> <Value 1>1</Value 1> <Value 2>0</Value 2> <Value 3>1</Value 3> <Value 4>0</Value 4> </Parent 1> <Parent 2> <Value 1>1</Value 1> <Value 2> 0</Value 2> <Value 2> 0</Value 2> <Value 3> 1</Value 3> <Value 4> 0</Value 4> </Parent 2> Any ideas on how to do this? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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