Subject: RE: [xsl] how can I compare two xml files ? From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Wed, 18 Apr 2001 15:32:59 +0100 |
I use James Clark's XML canonicalizer for this purpose, it is (or was) on www.jclark.com You could do it using XSLT if you always use the same processor; my interest was in comparing the output of different processors. There's also some kind of canonical comparison done in the XSLTMark benchmark. Mike Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of > Mengel Andre > (FV/SLM) * > Sent: 18 April 2001 13:24 > To: 'XSL-List@xxxxxxxxxxxxxxxxxxxxxx' > Subject: [xsl] how can I compare two xml files ? > > > Dear XSLT-Experts ! > > I want to compare two XML-files in order to test if they have > the same content. Is it possible to use XSLT in order to solve this > (I am not an XSLT-Expert) problem ? What I have in mind is to > transform > both XML-files by using an XSL-sheet. Then after processing I want to > compare > both transformed files byte for byte. > So the transformation would have to rearrange the attributes > in a unique > manner. > The structure of the xml-files I want to compare is very complex. > Does that imply that the XSL-file will also be very complex , > or is it > possible to use a kind of standard-transformation without any details > about the xml-files themselves ? > > > Thank you for your efforts > > Best regards > > André Mengel > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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