Subject: RE: [xsl] Using Result Tree Fragments as Node-set From: Mark Swardstrom <mark@xxxxxxxxxx> Date: Wed, 18 Apr 2001 10:37:51 -0700 |
Thanks - I should have mentioned I was using Xalan, they have an extension "nodeset()" (opposed to "node-set()") that seems to work. Now to debug my xsl... Thanks for the response. - Mark -----Original Message----- From: Jeni Tennison [mailto:mail@xxxxxxxxxxxxxxxx] Sent: Wednesday, April 18, 2001 12:12 AM To: Mark Swardstrom Cc: 'XSL-List@xxxxxxxxxxxxxxxxxxxxxx' Subject: Re: [xsl] Using Result Tree Fragments as Node-set Hi Mark, > Hi everyone. Is there a way to use the RTF as a node-set without > using the proprietary node-set() function? There's no way to turn an RTF into a node set without an extension function if you have a compliant XSLT 1.0 processor. As far as I know, Saxon still implements the "XSLT 1.1" Working Draft, and allows automatic conversion from RTF to node set. This is something that will probably be formally introduced to XSLT in XSLT 2.0. Part of the point of the EXSLT initiative is to standardise on a namespace for the node-set() function (i.e. make it non-proprietary), so that you can use it without limiting yourself to a particular processor. Have a look at http://www.exslt.org/common/. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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