Subject: Re: [xsl] copy-of question From: "Franz Figl" <frafi@xxxxxxxxxx> Date: Wed, 18 Apr 2001 23:17:41 +0200 |
Rick, there is nothing wrong with the copy-of: I want a full deep original table element, and I have it. But I want to exclude all the other tags! > Franz, > > xsl:copy-of gives a "deep" copy of the element and _all_ its descendants. > > xsl:copy gives a copy of only the element in question. > > See Mike Kay's "XSLT Reference" for details. > > I hope that helps, > > Rick Suiter > > > > > > "Franz Figl" <frafi@xxxxxxxxxx>@lists.mulberrytech.com on 04/18/2001 > 02:34:23 PM > > Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > Sent by: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > > To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> > cc: > Subject: [xsl] copy-of question > > > Hi all, > > how can I extract only one element in original form? > copy-of seems to work here, but I have all the other unwanted tags also as > plain text. > Is this related to the default rules? > > <xsl:template match="TABLE"> > <xsl:copy-of select="."/ > </xsl:template> > > Franz > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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