Subject: AW: [xsl] for-each with included variable From: "Machelett, Renato (FA.G+M-EP/ETK)" <fa-gm-renato.machelett@xxxxxxxxxxxxxxxxxxx> Date: Thu, 19 Apr 2001 15:26:18 +0200 |
Thank you David and Mike, David's solution didn't bring the result I expected, I'm not sure why, but the output stays exactly the same as before. Which I find unsettling - like always when I'm clueless. Mike's approach won't work because I cannot use key() inside a template. I'll try the generate-id() part once I've gotten more familiar with this whole thing, which might take a while as far as I can tell. I'm still struggling with the basics. :) For now I picked another solution (found it in the FAQ, which is a good one), that might not be overly elegant, but works. The variable now holds the entire expression, not just a list of single literals. IncludeMe.xsl: <xsl:variable name="myOPTypeList" select="(.//*[@OPTypeRef='Type1'])[1] | (.//*[@OPTypeRef='Type2'])[1] | (.//*[@OPTypeRef='Type3'])[1]"/> DoSomeStuff.xsl: <xsl:include href="IncludeMe.xsl"/> <xsl:for-each select="$myOPTypeList"> <!-- do some stuff --> </xsl:for-each> Not exactly the way I wanted it, but at least I have a central place for changes, and I have it when I need it - NOW. :) Renato > > <xsl:for-each select="(.//*[@OPTypeRef='Type1'])[1] | > > (.//*[@OPTypeRef='Type2'])[1] | (.//*[@OPTypeRef='Type3'])[1]"> > > <!-- do some stuff --> > > </xsl:for-each> > > > Someone else has pointed out your simple coding error, but how about a > completely different approach: > > <xsl:key name="OKtypes" > match="*[@OPTypeRef[.='Type1' or .='Type2' or .='Type3']]" > use="1"/> > > <xsl:for-each select="key('OKtypes', 1)[1]"> ... > > (This only works if ".//*" in your code is searching the > whole document: if > not, you could change the use= in the key to be the > generate-id() of the > relevant ancestor node.) > > Mike Kay > Software AG XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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