Subject: RE: [xsl] Transform min and max values to list? From: "Xuegen Jin" <xjin_imi@xxxxxxxxx> Date: Thu, 19 Apr 2001 11:10:21 -0400 |
Wow, that is enlightening. Are there a list of such tricks documented somewhere on the net? :-) -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Jeni Tennison Sent: Thursday, April 19, 2001 8:00 AM To: Michael Strasser Cc: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Transform min and max values to list? Hi Michael, > I want to transform this element: > > <number min="1" max="3"/> > > into this: > > <select> > <option>1</option> > <option>2</option> > <option>3</option> > </select> > > I have looked at for-each but its select attribute requires a node-set. Is > there a simple way to achieve what I want? Well, you could be terribly virtuous and use recursive templates. Have a template that creates the option element, taking a $number parameter (the number for the option) and a $max parameter (the maximum number that should be outputted. Use the $number to create the value of the option, and test the $max parameter to see whether you should move on to the next one: <xsl:template name="create-option"> <xsl:param name="number" select="1" /> <xsl:param name="max" select="1" /> <option><xsl:value-of select="$number" /></option> <xsl:if test="$number < $max"> <xsl:call-template name="create-option"> <xsl:with-param name="number" select="$number + 1" /> <xsl:with-param name="max" select="$max" /> </xsl:call-template> </xsl:if> </xsl:template> You can then call this template from the number-matching template, with the @min attribute giving the starting $number, and the @max attribute giving the $max parameter: <xsl:template match="number"> <select> <xsl:call-template name="create-option"> <xsl:with-param name="number" select="@min" /> <xsl:with-param name="max" select="@max" /> </xsl:call-template> </select> </xsl:template> So, that's the virtuous way. However, you can employ the Piez 'cheap hack' method (his words, not mine), and use xsl:for-each instead. All you need to do is construct a node set that consists of the right number of nodes, and then iterate over them. You can use the position() of the node you're looking at as the basis of the number you put in the option. One method would be: <xsl:variable name="random-nodes" select="document('')//*" /> <xsl:template match="number"> <xsl:variable name="min" select="@min" /> <xsl:variable name="nnodes" select="(@max - @min) + 1" /> <select> <xsl:for-each select="$random-nodes[position() <= $nnodes]"> <option> <xsl:value-of select="position() + $min - 1" /> </option> </xsl:for-each> </select> </xsl:template> I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list _________________________________________________________ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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