Subject: Re: [xsl] Re:Re: How to copy xml which attributes are processed with normalize-space function From: Oliver Becker <obecker@xxxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 20 Apr 2001 11:48:26 +0200 (MET DST) |
Hi Sun-fu, > -- output -- > > <list ClientID="aaa" EntityID="xxxx" FacilityID="A001" > xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882" <===these part of > output I would like to get rid of. > xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882" which are from the > namespace prefixes. > xmlns:rs="urn:schemas-microsoft-com:rowset" > xmlns:z="#RowsetSchema" xmlns:msxsl="urn:schemas-microsoft-com:xslt"> > </list> > <list>... > </list> > > what I like to see a more clean output such as: > > <list ClientID="aaa" EntityID="xxxx" FacilityID="A001"> > </list> > <list ClientID="bbbb" EntityID="yyyy" FacilityID="B001" > </list> just add the attribute exclude-result-prefixes="s dt rs z msxsl" to the xsl:stylesheet start tag: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882" xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882" xmlns:rs="urn:schemas-microsoft-com:rowset" xmlns:z="#RowsetSchema" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="s dt rs z msxsl"> Cheers, Oliver /-------------------------------------------------------------------\ | ob|do Dipl.Inf. Oliver Becker | | --+-- E-Mail: obecker@xxxxxxxxxxxxxxxxxxxxxxx | | op|qo WWW: http://www.informatik.hu-berlin.de/~obecker | \-------------------------------------------------------------------/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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