RE: [xsl] HTML in XML not getting to my html output.

Subject: RE: [xsl] HTML in XML not getting to my html output.
From: Meltem Kogelbauer <meltem.kogelbauer@xxxxxxxxxxxxxxxxxx>
Date: Tue, 24 Apr 2001 16:59:26 +0100
Here is another(I believe, more practical) solution.
<xsl:template match="/">

				<xsl:apply-templates select="//notes" />
<xsl:template match="notes">
	<xsl:copy-of select="node()" /><hr />



-----Original Message-----
From: Thomas B. Passin [mailto:tpassin@xxxxxxxxxxxx]
Sent: 23 April 2001 3:24 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] HTML in XML not getting to my html output.

All the xsl instructions you used display text content, that's why you don't
see the <b> tags.  Also the xsl:copy-of for the $separator is overkill,
since the separator is just text.  On the other hand, xsl:copy-of is just
what you want to pick up the <b> tags.  Here's a nice compact template that
does what you want:

<xsl:template match='/notes'>
   <xsl:for-each select='note'>
      <xsl:copy-of select='.'/>
      <xsl:if test='position()!=last()'><hr/></xsl:if>


Tom P

Robert Nicholson asked -

> Why when I have
> <note>
> <b>Please note that I am a British and Australian citizen who is a green
> card holder as of 12th May, 1999.</b>Also, email is my preferred method of
> correspondence.
> </note>
> does the bolding HTML tag not get in my translated html?
> This html it outputed thus
> <xsl:template match="notes">
> <p>
> <xsl:call-template name="separated-list">
> <xsl:with-param name="nodes" select="note"/>
> <xsl:with-param name="separator">
> <br/><br/>
> </xsl:with-param>
> </xsl:call-template>
> </p>
> </xsl:template>
> <xsl:template name="separated-list">
> <xsl:param name="nodes"/>
> <xsl:param name="separator"/>
> <xsl:for-each select="$nodes">
> <xsl:value-of select="normalize-space(.)"/>
> <xsl:if test="position() != last()">
> <xsl:copy-of select="$separator"/>
> </xsl:if>
> </xsl:for-each>
> </xsl:template>

 XSL-List info and archive:

 XSL-List info and archive:

Current Thread