RE: [xsl] xsl copy

["Michael Fitzgerald" <mike@xxxxxxxxxx>]

The identity transformation:

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

@* = any attribute; node() = any node().

See http://www.w3.org/TR/xslt#copying.

Good luck,

Mike

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of
> Kevin_Gutch@xxxxxxxxxxx
> Sent: Wednesday, April 25, 2001 8:39 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] xsl copy
> 
> 
> Is there a way to copy attributes without having to perform a deep copy
> (copy-of)?
> 
> 
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list