Re: [xsl] for-each question

[Ronald <ronald@xxxxxxxxxxx>]

You're not specifying you want both documents to be generated.
This is probably called the "xsl:for-each trap".

Maybe you can try to do without the xsl for-each?
xsl:value-of only gives you the first value!

Try xsl:apply-templates here, or another xsl:for-each commando.

If you really have to use xsl:for-each, why are you not specifying the xsl 
for-each as:
<xsl:for-each 
select="/eventsCalendar/eventRecord[eventID=$neweventID]/listDoc/document">
for it is the content of your for-each that has to be outputted for each 
document, and not for each listdoc.

I would suggest that you rewrite this fragment and try not to use 
xsl:for-each but xsl:apply-templates etc.

Ronald

At 12:34 PM 4/26/01 +0100, you wrote:
> I have the following xml:
> <eventsCalendar>
>    <eventRecord>
>                 <eventID>1</eventID>>
>                 ----
>                 <listDoc>
>                   <document href="C:\events1.doc">agenda.doc</document>
>                   <document href="C:\events2.doc">conference.doc</document>
>                 </listDoc>
>      </eventRecord>
> ----
> </eventsCalendar>
>
> and the following xsl:
> The parameter was set earlier
> -------
>  <td colspan="3" width="363">
>             <xsl:for-each
> select="/eventsCalendar/eventRecord[eventID=$neweventID]/listDoc/">
>             <font face="Arial, Helvetica, sans-serif" color="#000000"
> size="1">
>                         <a>
>                                 <xsl:attribute name="href"><xsl:value-of
> select="document/@href"/></xsl:attribute>
>                                 <xsl:value-of select="document"/>
>                         </a>
>                     </font>
>              </xsl:for-each>
>              </td>
>
> -----------
> Output:
> Just a link to agenda.doc is returned and not both documents. Any
> suggestions?
>
> Tanz
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list