Subject: Re: [xsl] xsl/xsql From: "Steve Muench" <Steve.Muench@xxxxxxxxxx> Date: Fri, 27 Apr 2001 15:49:36 -0700 |
Kevin, | I am trying to use an XSQL in my XSL but receive the following error. | | | javax.xml.transform.TransformerException: No scheme found in URI: | | My reference to the XSQL is as follows: | | "'http://localhost:####/xsql/demo/myTests/exists.xsql'" | | I have seen several samples and I seem to be doing everything correctly. Presumably you're trying to "suck" in dynamic XML data into your XSL stylesheet with something like: <xsl:variable name="data" select="document('http://localhost:####/xsql/demo/myTests/exists.xsql')"/> This should work fine. I just tried the following stylesheet: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:variable name="x" select="document( 'http://ws5.olab.com/xsql/demo/airport/airport.xsql?airport=xml')"/> <xsl:copy-of select="$x"/> </xsl:template> </xsl:stylesheet> and got the answer: <Ok> <Airport num="1"> <Code>XML</Code> <Description>Minlaton, Sa, Australia</Description> </Airport> </Ok> Try changing the the "airport=xml" part of the URL to airport=SFO or airport=BOS or any valid airport three-letter-code. P.S. Make sure your proxy is set correctly if you want to try the above example from behind a corporate firewall. ______________________________________________________________ Steve Muench, Lead XML Evangelist & Consulting Product Manager BC4J & XSQL Servlet Development Teams, Oracle Rep to XSL WG Author "Building Oracle XML Applications", O'Reilly http://www.oreilly.com/catalog/orxmlapp/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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