Subject: Re: [xsl] Reverse order From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 1 May 2001 15:05:44 +0100 |
> I thought the XPath expression in the for-each statement should return a > reverse oder of all parts No, it returns a node set, and sets are unordered. for-each always iterates through the supplied node set in document order... unless you supply an xsl:sort element you can reverse the order with the order attribute on xsl:sort. David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Control Centre. For further information visit http://www.star.net.uk/stats.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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