Subject: [xsl] Re: XML version 1.4 (was: your mail) From: Goetz Bock <bock@xxxxxxxxxxx> Date: Wed, 9 May 2001 18:54:28 +0200 |
On Wed, May 09 '01 at 18:24, Stephane.Le-Deaut@xxxxxxxxxx wrote: > My DTD starts like this : > > <?xml version="1.0" encoding="iso-8859-1"?> > <!--******************************************************--> > <!--* "commonDelivery.dtd" *--> > <!--******************************************************--> > <!ENTITY % commonDeliveryVersion "1.4"> > .... > .... > > > I would like to build an XML file with the version "1.4". > > How to get with XSL the number "1.4" ? > Is it possible ? For me it's not totaly clear, what you want ... is it: <?xml version="1.4"?> <commonDelivery> ... </commonDelivery> that's not possible, XML version 1.4 is not defines, we're all happy to still have 1.0 around. it you want to: <?xml version="1.0"?> <commonDelivery version="1.4"> ... </commonDelivery> that's basic XSL-T you can learn from various places (the spec, Michael's book, introductions on the www ...) if you want: <xsl:text>&commonDeliveryVersion;</xsl:text> this will not work, as this entity is not declared in your XSL-T file, only in the DTD for your (source) document. Well, just blubbering, Goetz.
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