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Subject: [xsl] Problem of syntax of filter ? From: Stephane.Le-Deaut@xxxxxxxxxx Date: Wed, 16 May 2001 10:13:36 +0200 |
I've got this XML file :
<DownloadTable version="1.4">
<DownloadTableDescription downloadTableVersion="" />
<Table>
<DownloadTableName downloadType="PENE_NOT_OCB" fileName="peNeNotOcbFot.xml"/>
<DownloadTableName downloadType="SGDTR_NOT_OCB" fileName="sgdtrNotOcbFot.xml"/>
<DownloadTableName downloadType="EL_NOT_OCB" fileName="elNotOcbFot.xml"/>
<DownloadTableName downloadType="PE_OCB" fileName="peOcbFot.xml"/>
<DownloadTableName downloadType="PE_SDIFF" fileName="peSdiffFot.xml"/>
<DownloadTableName downloadType="PE_GEN" fileName="peGenFot.xml"/>
<DownloadTableName downloadType="SGDTR_OCB" fileName="sgdtrOcbFot.xml"/>
<DownloadTableName downloadType="CDP_OCB_INC" fileName="cdpOcbIncFot.xml"/>
<DownloadTableName downloadType="CDP_OCB_COMP" fileName="cdpOcbCompFot.xml"/>
</Table>
</DownloadTable>
I would like to recover the attribute fileName only if downloadType = EL_NOT_OCB
I've tried this code in order to select the element :
<xsl:variable name="matchingDownloadTableName"
select="$dtableFile//DownloadTableName
[(@downloadType=$downloadType)]"/> (with $downloadType=EL_NOT_OCB)
Then, I build my output tree like this :
<xsl:for-each select="$matchingDownloadTableName">
<DownloadTableName downloadType="{@downloadType}"
fileName="{@fileName}"/>
</xsl:for-each>
But the result of my output tree is empty !
I don't understand why my code doesn't work.
Is it my filter good ?
Thanks for your help.
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