Re: [xsl] xsl:copy-of

Subject: Re: [xsl] xsl:copy-of
From: David Carlisle <davidc@xxxxxxxxx>
Date: Mon, 21 May 2001 10:32:03 +0100
>   <xsl:template match="/">
> 	<xsl:copy-of select="document()" />


you want select="." there not select="document()" as . will be the root
note of your input tree, however it won't do what you ask:


> This does the job fine. Now I want to make my XSLT more generic so I don't
> have to specifically say that the "<BODY>" is a CDATA section. Basically I
> want an exact copy of the original document whatever the original document
> may be.

For that you want to use your file system copy command:-)
XSLT can _not_ do an exact copy of the input syntax. It does not see the
original file, just the result of parsing it with an XML parser. So it
sees the same input if you go <![CDATA[a<b]]> or a&lt;b as these are the
same thing. Incidentally why do you care whether it is output as CDATA
or as characters or references? CDATA is a shorthand for hand authoring
to save writing &lt; so often but it is fairly pointless in machine
generated XML.

David

_____________________________________________________________________
This message has been checked for all known viruses by Star Internet
delivered through the MessageLabs Virus Scanning Service. For further
information visit http://www.star.net.uk/stats.asp

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread