Subject: Re: [xsl] whitespace as a parameter to a template (replace linefeed with li nefeed tab) From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Thu, 31 May 2001 11:59:27 +0100 |
Hi James, > I am making the call to my "do-replace" template as follows: > <xsl:call-template name="do-replace"> > <xsl:with-param name="text" select="$x"/> > <xsl:with-param name="replace"> </xsl:with-param> > <xsl:with-param name="by"> 	</xsl:with-param> > </xsl:call-template> > > I suspect that the XML parser is converting my the whitespace in the > "replace" and "by" parameters to a single space or an empty string. > What is the proper way to preserve the white space in parameters > being passed into a template? You'll probably find it easiest to just use the select attribute to set the parameter values rather than the content of the xsl:with-param: <xsl:call-template name="do-replace"> <xsl:with-param name="text" select="$x" /> <xsl:with-param name="replace" select="' '" /> <xsl:with-param name="by" select="' 	'" /> </xsl:call-template> You could equally use xsl:text in the content of the xsl:with-param, as others have shown, but it's longer. I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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