Subject: [xsl] Counting unique node values using XSLT? From: "Brucato, Greg" <GBrucato@xxxxxxxxxxxx> Date: Fri, 1 Jun 2001 16:13:16 -0400 |
I am using the count() function to successfully count the number of nodes produced in XML data created using Java. However, I now have a situation where some of the values are duplicates. Is there any way to count only unique values? Example: The count should be 6 not 8 since there are two duplicates in the second fragment. <xsl:value-of select="count(trunk-groups/tg)"/> ... <trunk-groups> <tg>T1-1-1-1</tg> <tg>T1-1-1-2</tg> <tg>T1-1-1-3</tg> <tg>T1-1-1-4</tg> </trunk-groups> ... <trunk-groups> <tg>T1-1-1-2</tg> <tg>T1-1-2-3</tg> <tg>T1-1-1-4</tg> <tg>T1-1-2-8</tg> </trunk-groups> Thanks, Greg XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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