Subject: RE: [xsl] Re: How to define a xsl:sort's order attribute using a variable From: Mike McGraw <mmcgraw@xxxxxxx> Date: Wed, 27 Jun 2001 15:12:08 -0400 |
Thanks very much- this solved the problem =) <xsl:for-each select="person/*[name()=$sortBy]"> <xsl:sort select="." order="{$sortOrder}"/> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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