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RE: [xsl] count all the following nodes of a perticular parent

Subject: RE: [xsl] count all the following nodes of a perticular parent
From: "Ben Robb" <b.robb@xxxxxxxxxx>
Date: Thu, 28 Jun 2001 11:04:33 +0100
Try count() ;)

count(following::*)

> -----Original Message-----
> From: Jayaranga Subasinghe [mailto:jayarangas@xxxxxxxxxxxxx]
> Sent: 28 June 2001 10:52
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] count all the following nodes of a perticular parent
> 
> 
> hello,
> i want to count all the following nodes from the current node 
> of the same
> parent
> can anybody give me a way to do this?
> thank you
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
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RE: [xsl] count all the following n, Wendell Piez Thread [xsl] Count all the following nodes, Jayaranga Subasinghe
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