Subject: [xsl] adressing attributes From: Michael Zehrer <zehrer@xxxxxxxxxxxxxxxxxx> Date: Fri, 29 Jun 2001 12:31:05 +0200 |
Thanks to the FAQ I learned howto "Making balanced two-column tables from one-column data", but I also want to list one attribute and really don't know how to address it. This is my XML: <page> <element id="sometext">content</element> ... </page> and my XSL is: <xsl:variable name="t-size" select="count(//element)"/> <xsl:variable name="half" select="ceiling($t-size div 2)"/> <table> <xsl:for-each select="//element[position() <= $half]"> <xsl:variable name="here" select="position()"/> <tr> <td><xsl:value-of select="@id"/></td> <td><xsl:value-of select="."/></td> <td><xsl:value-of select="@id"/></td> <td> <xsl:choose> <xsl:when test="../element[$here+$half]"> <xsl:value-of select="../element[$here+$half]"/> </xsl:when> <xsl:otherwise></xsl:otherwise> </xsl:choose> </td> </tr> </xsl:for-each> </table> Sure, at the moment the @id in the 3rd cell gives the same value as the one in the first cell, but it should contain the value of the id attribute of the 4th cell element. I tried to construct something similar to the 4th cell xsl code, but it just don't work. Can someone explain it to me? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] what can you do with {} a, David Carlisle | Thread | AW: [xsl] adressing attributes, Michael Zehrer |
Re: [xsl] what can you do with {} a, cutlass | Date | Re: ie namespace and doctype was Re, David Carlisle |
Month |