[xsl] A simple solution (Was: Re: One for tomorrow :-) )

Subject: [xsl] A simple solution (Was: Re: One for tomorrow :-) )
From: Dimitre Novatchev <dnovatchev@xxxxxxxxx>
Date: Tue, 3 Jul 2001 12:17:19 -0700 (PDT)
Daniel Newman wrote:

> My XML (I know you've all already got it :), is:
> <Item id="2">
> 	<HIN>G0200328400</HIN>
> 	<PostCode>EC2A 1BR</PostCode>
> 	<NameAddress1>SMITH &amp; WILLIAMSON NOMINEES</NameAddress1>
> 	<NameAddress2>LIMITED &lt;CH&gt;,</NameAddress2>
> 	<NameAddress3>10 ACACIA AVENUE</NameAddress3>
> 	<NameAddress4>HUTTINGDON HILL</NameAddress4>
> 	<NameAddress5>LONDON</NameAddress5>
> 	<NameAddress6/>
> 	<NameAddress7/>
> </Item>
> And my problem is, that I want to display NameAddress1, and also need to
> concat all following Nodes that end in a comma. So I need to do a:

Hi Daniel,

Actually, it is quite simple -- do note the XPath expression for all "following
Nodes" (in this case following-sibling::*) the text of which ends in a comma -- this
uses a combnation of the substring() and string-length() functions.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:template match="/">
    <xsl:for-each select="/Item/NameAddress1">
      <xsl:value-of select="."/>
         <xsl:value-of select="."/>

Hope this helped.

Dimitre Novatchev.

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