Subject: RE: [xsl] Beginner's question From: Jarno.Elovirta@xxxxxxxxx Date: Thu, 12 Jul 2001 11:38:57 +0300 |
> Suppose I have an XML document with a complex DTD. The DTD > contains a tag > deep in the hierarchy called <code>. How would I transform > the XML doc to > another XML doc that was identical except for having the > <code> tag removed? <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:apply-templates select="node()" /> </xsl:template> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="code"> <xsl:apply-templates select="@*|node()"/> </xsl:template> </xsl:stylesheet> Will just remove the code element and copy it's content. If you want to remove code element and it's content, use <xsl:template match="code" /> instead. Note that the stylesheet will not preserve the doctype declaration and encoding, so the output will not be identical except for the code element missing. Jarno XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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