RE: [xsl] Beginner's question

Subject: RE: [xsl] Beginner's question
From: Jarno.Elovirta@xxxxxxxxx
Date: Thu, 12 Jul 2001 11:38:57 +0300
> Suppose I have an XML document with a complex DTD. The DTD 
> contains a tag 
> deep in the hierarchy called <code>. How would I transform 
> the XML doc to 
> another XML doc that was identical except for having the 
> <code> tag removed?

<?xml version="1.0" encoding="ISO-8859-1"?> 
<xsl:stylesheet version="1.0"

<xsl:template match="/">
  <xsl:apply-templates select="node()" />

<xsl:template match="@*|node()">
    <xsl:apply-templates select="@*|node()"/>

<xsl:template match="code">
  <xsl:apply-templates select="@*|node()"/>


Will just remove the code element and copy it's content. If you want to
remove code element and it's content, use

<xsl:template match="code" />

instead. Note that the stylesheet will not preserve the doctype declaration
and encoding, so the output will not be identical except for the code
element missing.


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