Re: [xsl] How to output a xmlns:prefix attribute (special case)

Subject: Re: [xsl] How to output a xmlns:prefix attribute (special case)
From: David Carlisle <davidc@xxxxxxxxx>
Date: Sat, 14 Jul 2001 12:13:03 +0100

Thanks David, it works (after fixing the typo) :-)
Here there also a way to add a *default* namespace declaration to the
xsd:schema element ? In this case there is no dummy name x, just an URI

Yes just use the default namespace in the variable and fish it out using
namespace::* but you never want to do this. You sometimes need to use
this trick to produce namespace nodes for prefixes that are used in
_content_ rather than  element or attribute names but (surely) no one
would use the default namespace and not have _any_ elements in that
namespace would they? If there are elements in the namespace in the
result tree th enamespace will be added automatically.


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