Re: [xsl] Conditional variable assignment with node-set as value

Subject: Re: [xsl] Conditional variable assignment with node-set as value
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 18 Jul 2001 09:22:59 +0100
> select="saxon:node-set(RFQDomainAttributeDefinition[@Domain
> = 'lbid']/ExtendedAttributeDefinition)" />

You can't use (and don't need) node-set there: node-set() converts
a result tree fragment to a node set, but an XPath expression always
returns a node set (or at least, it never returns a result tree

If you remove all occurrences of saxon:node-set then your code looks
right. On th eother hand If what you want is a node set as a result you
would be better to use xsl:variable with a select expression rather than
content, otherwise you will have to use
every time you use it.

It looks likey you just want

<xsl:variable name="x"

<xsl:variable name="extended-attrs-bid" select="
 RFQDomainAttributeDefinition[$x][@Domain =
= generate-id(key('extended-attrs-bid-index',


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