Subject: Re: [xsl] Deep copy that excludes the element tag From: Laurence O Garfield <lgarfiel@xxxxxxxxxxxxxxxxxxx> Date: Wed, 25 Jul 2001 13:55:28 -0500 (CDT) |
On Wed, 25 Jul 2001, Jason Macki wrote: > Hello, > > Is it possible to use XHTML to transform this: > > <myhtml>This is some <b>HTML</b>!</myhtml> > > Into this: > > This is some <b>HTML</b>! > > In other words, I'd like to do a deep copy (a copy that includes any > elements within the element) of the contents of "myhtml" while excluding > the tag for the "myhtml" element. > > Thanks, > Jason Try the following: <xsl:template match="myhtml"> <xsl:apply-templates mode="copyall"/> </xsl:template> <xsl:template match="@*|*|text()" mode="copyall"> <xsl:copy> <xsl:apply templates select="@*|*|text()" mode="copyall"/> </xsl:copy> </xsl:template> That would apply the identity transformation ("keep the same") for only sub-nodes of myhtml, and anywhere else that you called apply-templates with the copyall mode. I think that should work, anyway. --Larry Garfield XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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