Re: [xsl] document function and counting

[Francis Norton <francis@xxxxxxxxxxx>]

How about something like this?

<untested>
...
<xsl:for-each select="document('foo-1.xml')//item |
document('foo-2.xml')//item" >
	<xsl:value-of select="position()" /> 
	<xsl:copy-of select="." />
</xsl:for-each>
...
</untested>

Francis.

Christine Donica wrote:
> 
> I am trying to use the document function to pull in the result trees of
> other documents and then I want to number things across the entire new
> document in one pass.
> 
> For example say I have a file called master.xml which contains uri's to
> other documents called foo1.xml and foo2.xml.  Say foo1.xml and foo2.xml
> each contain a list of <item> tags.
> 
> I want the output of the transformation to be a document which contains
> all of the <item>s of both foo1.xml and foo2.xml AND I want to number them
> continuously from the top to the bottom.  I want to do this in one pass of
> a stylesheet.
> 
> I can pull foo1.xml and foo2.xml into the output file using document().
> Also, if all of the items are already in the same document I can easily
> number them using the <xsl:number> tag.  However, it is not possible to do
> both in the same run of the stylesheet because xsl:number does not seem to
> have access to the elements in main.xml and either foo1.xml or foo2.xml at
> the same time. So I can reach my goal if I write two stylesheets and run
> them one after each other, but I don't want to do that.
> 
> Alternatively, I have tried using parameters to pass a number into the
> item template.  However, I don't know how to get this information from the
> point where the template matches an <item> in foo1.xml to a point where it
> matches <item> in foo2.xml.  That is, I cannot pass parameters up the
> tree.
> 
> Could someone please explain how I should do this?  Or, is it even
> possible?
> 
> Thank you so much for your time.
> 
> Sarah Coppin
> 
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