RE: [xsl] get the name of a node which I know the value

["KIENLE, STEVEN C [IT/0200]" <steven.c.kienle@xxxxxxxxxxxxx>]

I think what you want is something like:

<xsl:variable name="CurrentFile"
                       select="name(//*[@* =
'C:/XML/currentAuthentifiedPackageDescriptor_N2.xml'])"/>

This will search all of the nodes in the tree for one which has a attribute
with the value specified and returns the name of that node.  I am assuming
that the file name is complete, in which case the starts-with function is
not required.

	Steve

-----Original Message-----
From: Stephane.Le-Deaut@xxxxxxxxxx [mailto:Stephane.Le-Deaut@xxxxxxxxxx]
Sent: Monday, August 20, 2001 11:41 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] get the name of a node which I know the value




I have this xml file :

<?xml version="1.0" encoding="ISO-8859-1"?>
<XslParameter>
  <InputFile
 
currentAuthentifiedPackageDescriptor1="C:/XML/currentAuthentifiedPackageDesc
riptor_N1.xml"
 
currentAuthentifiedPackageDescriptor2="C:/XML/currentAuthentifiedPackageDesc
riptor_N2.xml"
 
referenceAuthentifiedPackageDescriptor_Nectar="C:/XML/referenceAuthentifiedP
ackageDescriptor_Nectar.xml"
    automate="C:/XML/automate.xml"
    user="C:/XML/user_prg_dha.xml"/>
  <OutputFile
    subsetDescriptor="C:/XML/subsetDescriptor.xml"
    xslTrack="C:/XML/XslTrack_Test_makeSubsetDescriptor_01.xml"
    xslError="C:/XML/XslError_Test_makeSubsetDescriptor_01.xml"/>
  <Parameter
    signature="C:/XML/Signature.xml"/>
</XslParameter>


I know the value of the "currentAuthentifiedPackageDescriptor2" attribute
and I would like to assign a variable with the name of the node.
I tried to use name() function like this
         <xsl:variable name="CurrentFile"
 
select="name()[starts-with(@*,'C:/XML/currentAuthentifiedPackageDescriptor_N
2.xml')]"/>
but it does not work.

Please help me.



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