Subject: Re: [xsl] document() path created from xml From: "Swen Thuemmler" <Swen.Thuemmler@xxxxxxxxxxxx> Date: Tue, 4 Sep 2001 13:01:47 +0200 (CEST) |
On Tue, 4 Sep 2001, Jeroen Janssen wrote: > Sorry, I made a mistake with the xsl example I sent (apart from the fact > that it doesn't work :-) stupid me!! > > My problem is that I want to take the id from one xml document and I want to > use that id to load another document, something like this: > > <xsl:variable name="path"> > document('../data/institutions/institutions_country<xsl:value-of > select="country/@id"/>.xml')/institutions > </xsl:variable> > > <xsl:apply-templates select="$path"/> Try <xsl:variable name="filename" select="concat('../data/institutions/institutions_country',country/@id)"/> <xsl:variable name="path" select="document($filename)"/> <xsl:apply-templates select="$path"/> You need to declare the variable $path with the select="..." syntax to get a node-set, not a result tree fragment. Hope this helps. --Swen XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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