RE: [xsl] How do you get the non-transformed character entit

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RE: [xsl] How do you get the non-transformed character entity out of MSXML3.0

Subject: RE: [xsl] How do you get the non-transformed character entity out of MSXML3.0
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Mon, 17 Sep 2001 14:21:57 +0100

> until transformation it indeed has the value of &lt;
> otherwise it would not load into the parser
> nor would the parser correctly transform it....

No, the attribute is written as "&lt;" in the source file but as soon as it
is parsed (i.e., as soon as it is recognized as an attribute) it has the
value "<".

Parsers do not do transformation, I think you are confusing the XML parser
with the XSLT processor. Understanding the distinction is absolutely crucial
here.

Mike Kay


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
RE: [xsl] How do you get the non-transformed character entity out of MSXML3.0, (continued) jdgarrett - Mon, 17 Sep 2001 12:27:41 -0500 David Carlisle - Mon, 17 Sep 2001 20:24:20 +0100 Mike Brown - Mon, 17 Sep 2001 23:51:25 -0600 (MDT) Francis Norton - Tue, 18 Sep 2001 09:52:55 +0100 Michael Kay - Mon, 17 Sep 2001 14:21:57 +0100 <= jdgarrett - Mon, 17 Sep 2001 12:36:57 -0500 Chris Bayes - Mon, 17 Sep 2001 19:27:24 +0100 Chris Bayes - Wed, 19 Sep 2001 15:53:36 +0100 Michael Kay - Mon, 17 Sep 2001 19:52:08 +0100

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RE: [xsl] How do you get the non-transformed character entity out of MSXML3.0, (continued)

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