Re: [xsl] questions?

Subject: Re: [xsl] questions?
From: "Christopher R. Maden" <crism@xxxxxxxxx>
Date: Mon, 17 Sep 2001 21:58:25 -0700
At 21:29 17-09-2001, Mihir D. Gore wrote:
If i have a operation like "insert node n as the i th  child of node p" ,
what will be the the xsl?

To repeat a FGA[*], XSLT can't change the source. It reads the source and writes output.


for example
<book>
        <author>P.G.Wodehouse</author>
        <name>Good Morning Jeeves</name>
        <price>20</price>
</book>

if i  add the node <review></review> as the 3rd child of book then the xsl
will be

<book>
        <author>P.G.Wodehouse</author>
        <name>Good Morning Jeeves</name>
        <review>Some comments here</review>
        <price>20</price>
</book>

What you want to do is copy the book, with the review added. You could do this by starting with the identity transform (see the XSLT Recommendation) and adding


<xsl:template match="book">
  <xsl:copy select=".">
    <xsl:apply-templates select="*[position() &lt; 3]"/>
    <review>Some comments here</review>
    <xsl:apply-templates select="*[position() >= 3]"/>
  </xsl:copy>
</xsl:template>

-Chris

[*] Frequently given answer.
--
Christopher R. Maden, Principal Consultant, HMM Consulting Int'l, Inc.
DTDs/schemas - conversion - ebooks - publishing - Web - B2B - training
<URL: http://www.hmmci.com/ > <URL: http://crism.maden.org/consulting/ >
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