Re: [xsl] Comma delimited parameters...

Subject: Re: [xsl] Comma delimited parameters...
From: "cutlass" <cutlass@xxxxxxxxxxx>
Date: Wed, 19 Sep 2001 11:39:18 +0100
i think using the substring-before() is what u want to use to crack this

see this technique in action at;

http://www.dpawson.co.uk/xsl/sect2/N1755.html

cheers, jim fuller

----- Original Message -----
From: "Casadome, Francisco Javier" <Francisco.Casadome@xxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, September 18, 2001 3:11 PM
Subject: [xsl] Comma delimited parameters...


> Hi all,
>
> I have an XSL receiving parameter that is a list of names separated by
> commas, like this:
> name1,name2,name3,name4,name5,name6,
> (note that the last one also have a comma at the end)
>
> Then I have a XML file with nodes that may or may not have these names as
> childs, like this:
>
> <myXML>
> <node1>
> <name1>XXX</name1>
> <name3>CCC</name3>
> </node1>
> <node2/>
> <node3>
> <name3>AAA</name3>
> <name6>QQQ</name6>
> </node3>
> </myXML>
>
> What I want to do is to create a TAB-separated file with all the names in
> the parameter as the first line, like this:
>
> -----------------------------------
> name1 name2 name3 name4 name5 name6
> -----------------------------------
> XXX CCC
>
> AAA QQQ
> -----------------------------------
>
> This is the XSL I have right now:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> <xsl:output method="text" omit-xml-declaration="yes" indent="no"/>
> <xsl:param name="Fields"/>
>
> <xsl:key name="AllPossibleFields" match="Entry/*" use="name()"/>
>
> <xsl:template match="Entries">
> <xsl:apply-templates select="Entry/*[count(. |
> key('AllPossibleFields',name())[1]) = 1]"/>
> <xsl:text>&#013;&#010;</xsl:text>
> <xsl:for-each select="Entry">
> <xsl:for-each select="*">
> <xsl:if
> test="contains($Fields,concat(name(),','))">
> <xsl:value-of
> select="."/><xsl:text>&#009;</xsl:text>
> </xsl:if>
> </xsl:for-each>
> <xsl:text>&#013;&#010;</xsl:text>
> </xsl:for-each>
> </xsl:template>
>
> <xsl:template match="*">
> <xsl:if test="contains($Fields,concat(name(),','))">
> <xsl:value-of
> select="name()"/><xsl:text>&#009;</xsl:text>
> </xsl:if>
> </xsl:template>
>
> </xsl:stylesheet>
>
> Here you can see that what I do is to check if the current node plus a
comma
> is in the parameter list using the contains() function. I do this because
I
> don't know how to split this string without using an embed VBScript.
> Also, I don't get name2, name4 and name5 in the header row, because there
> isn't any node with such childs.
>
> Any great ideas ?
>
> Thanks in advance,
> Frank.
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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