RE: [xsl] Get parent's node position

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RE: [xsl] Get parent's node position - Urgent

Subject: RE: [xsl] Get parent's node position - Urgent
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Wed, 26 Sep 2001 21:28:05 +0100

> Ok Mike, thanks a lot. Excellent!!!
> And what I would make to get a position of grand-parent??
> 
select="count(parent::*/parent::*/preceding-sibling::*)"

of course.

Or you can abbreviate parent::* to ".."

Mike Kay 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
[xsl] Get parent's node position - Urgent Paulo Henrique S. Bermejo - Tue, 25 Sep 2001 12:03:48 -0300 Michael Kay - Wed, 26 Sep 2001 16:37:01 +0100 Paulo Henrique S. Bermejo - Tue, 25 Sep 2001 13:11:26 -0300 Michael Kay - Wed, 26 Sep 2001 21:28:05 +0100 <= Gordon Stewart - Wed, 26 Sep 2001 17:18:09 +0100 Jörg Heinicke - Wed, 26 Sep 2001 23:17:15 +0200 <Possible follow-ups> Paulo Henrique S. Bermejo - Wed, 26 Sep 2001 15:52:25 -0300

Current Thread

[xsl] Get parent's node position - Urgent
- Paulo Henrique S. Bermejo - Tue, 25 Sep 2001 12:03:48 -0300
  - Michael Kay - Wed, 26 Sep 2001 16:37:01 +0100
    - Paulo Henrique S. Bermejo - Tue, 25 Sep 2001 13:11:26 -0300
      - Michael Kay - Wed, 26 Sep 2001 21:28:05 +0100 <=
    - Gordon Stewart - Wed, 26 Sep 2001 17:18:09 +0100
      - Jörg Heinicke - Wed, 26 Sep 2001 23:17:15 +0200
  - <Possible follow-ups>
  - Paulo Henrique S. Bermejo - Wed, 26 Sep 2001 15:52:25 -0300

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