Subject: [xsl] RE: Unique question From: Darren Hayduk <dhayduk@xxxxxxxxxxxxxxx> Date: Fri, 5 Oct 2001 14:15:34 -0400 |
Thanks to Joerg and Dimitre for your thoughts on my count unique question. After posting my question, I started playing with Saxon and temporary node-sets to solve the problem, and it seems much easier with v1.1: <xsl:for-each select="/groups/group"> <xsl:variable name="indexes"> <xsl:for-each select="*/*[@index!='']"> <xsl:copy> <xsl:value-of select="@index"/> </xsl:copy> </xsl:for-each> </xsl:variable> <xsl:if test="count(*/*[@index!='']) != count($indexes/*[not(.=preceding::*)])"> <!-- ERROR --> </xsl:if> </xsl:for-each> -----Original Message----- Now, when I'm completely awake, I see that the problem was to count the unique "index" attributes ***within a group***. <xsl:key name="kIndex" match="@index" use="concat(generate-id(../../..), '~',.)"/> Then if $x contains the position of the "group", for which we need to know the count of unique "index" attributes, the following XPath expression returns this count: count( /groups/group[$x]/*/*/@index[generate-id() = generate-id(key('kIndex', concat(generate-id(/groups/group[$x]), '~', .) )[1] ) ] ) XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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