Subject: Re: [xsl] outputting nodes with attribute - supressing the rest From: Eric Smith <Eric.Smith@xxxxxxxxxxxx> Date: Wed, 10 Oct 2001 20:19:25 +0200 |
According to Jörg Heinicke on Wed, Oct 10, 2001 at 07:57:40PM +0200: | What are you doing at the moment in your XSLT? | various failed things like <xsl:template match="section[@render != 'full']"/> And other contortions. | <xsl:template match="section[@render]"> | <!-- transform it to XSL-FO --> | </xsl:template> | | <xsl:template match="section[not(@render)]"/> | <!-- this means do nothing with it --> | geronimo! Is it possible to suppress *all* nodes that do not have the @render in a single template - <xsl:template match="*[not(@render)]"/> matches everything :( thanx -- Eric Smith - See mail headers for processors used XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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