Re: [xsl] Are these two the equivalent?

[Jörg Heinicke <joerg.heinicke@xxxxxx>]

Hi Nicholas,

you must divide the "@style"s in the second example not by '|' but by 'or'.

Joerg

> Hello All,
> I have two ways of what I think should achieve the same result
>
> Example 1 gives me what I want, Example 2 does not. To me they are the
> same...If they are different, could someone explain to me why the second
> does not give me what I want.
>
> Thanks in advance,
> Nicholas Waltham
>
> Example 1:
> <xsl:template
>
match="p[@style='L1'][preceding-sibling::p[last()][@style='L1']|preceding-si
> bling::p[last()][@style='L2']|preceding-sibling::p[last()][@style='L3']]">
> <xsl:apply-templates/>
> </xsl:template>
>
> Example 2:
> <xsl:template
>
match="p[@style='L1'][preceding-sibling::p[last()][@style='L1'|@style='L2'|@
> style='L3']]">
> <xsl:apply-templates/>
> </xsl:template>


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