Subject: [xsl] selecting nodes - syntax? From: "Denis Kranjcec" <denis.kranjcec@xxxxxx> Date: Mon, 15 Oct 2001 10:55:51 +0200 |
Hello everyone. I have problem with syntax when I want to select nodes. Here is example XML: <main> <list> <a code="1" priority="10" .../> <a code="2" priority="7" .../> <a code="3" priority="8" .../> <a code="4" priority="3" .../> <a code="5" priority="5" .../> </list> <elem> <b> ... <a code="1"/> <a code="3"/> ... </b> <b> ... <a code="4"/> <a code="5"/> <a code="3"/> ... <!-- hundreds of elements <b> --> </b> ... </elem> </main> Every element <a> have lots of attributes (XSL-FO properties). There is cca. 20 different elements <a>. Element <b> could have several elements <a>. Because of hundreds of elements <b> I don't want that there is copy of <a> in every <b>. I would like to have only attribute @code in element <a> that is same as @code in <a> with all properties. I want to select, for every <b> element, element <a> with lowest priority. I tried with something like this: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:apply-templates select="main/elem/b"/> </xsl:template> <xsl:template match="b"> <xsl:variable name="selected"> <xsl:for-each select="/main/a[@code = ./a/@code]"> <!-- I guess that problem is that node . isn't <b> --> <xsl:sort data-type="number" select="@priority" order="ascending"/> <!-- debug --> debug[<xsl:value-of select="."></xsl:value-of>] <xsl:if test="position()=1"> <xsl:value-of select="./@code"/> </xsl:if> </xsl:for-each> </xsl:variable> selected[<xsl:value-of select="$selected"/>] </xsl:template> </xsl:stylesheet> I don't know syntax to select element <a> with all properties. What is correct syntax? Any help is appreciated. Thanks in advance, Denis P.S. Sorry for my lousy english :-) XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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