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Subject: Re: [xsl] reordering output (Again) From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Mon, 22 Oct 2001 14:34:03 +0100 |
Goetz Block wrote:
> On Mon, Oct 22 '01 at 14:42, Eric Smith wrote:
>> In short, perhaps someone may advise:
>> Is reordering of nodes in the output possible?
> Yes.
>
> But could you be more elaborated on what and how you want to
> reorder. If you have a specific criteria, you can use <xsl:for-each
> sort=''>, but it might be more complicated than this.
Goetz meant:
<xsl:for-each select="...">
<xsl:sort select="..." />
...
</xsl:for-each>
You can also use xsl:sort within xsl:apply-templates to change the
order in which nodes are processed with templates.
I hope that helps,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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