Subject: Re: [xsl] simple tree problem ... From: Jörg Heinicke <joerg.heinicke@xxxxxx> Date: Wed, 24 Oct 2001 22:42:41 +0200 |
<xsl:template match="snip"> <xsl:apply-templates select="descendant::position"> <xsl:sort select="count(ancestor::position)"/> </xsl:apply-templates> </xsl:template> <xsl:template match="position"> <!-- do what you want --> </xsl:template> Hope this helps, Joerg > Well, a simple newbie question: > > First there was a tree ... > <snip> > <position> 1 > <position> 2 > <position/> 3 > </position> > <position/> 4 > </position> > <position/> 5 > </snip> > > (values only to explain sample) > > Now I want first the positions 1 and 5 , than 2 and 4 and > last but not least the 3rd one. (From parent to all childen > and their children ...) > > One problem: I don't know the maximum child levels (here 3), > they can be different (2 - 4 levels). How can I count them? > > Output: <xsl:for-each select="./position"> for the first > childs ... but how do I get through all the other levels? > > Thanks for help. > > Ingo XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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